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Se han recorrido 5/6 por lo tanto quedan por recorrer 1/6
sea un multiplo se 2 y 3 :2 x 3 = 6
1/3 =2/6
1/2 =3/6
3/6+2/6=5/6
6/6-5/6 =1/6
falta 1/6 de el camino.