Question

diketahui akar-akar kuadrat adalah x1 = 2 + √3/2 dan x2 = 2 - √3/2 persamaan kuadrat yang dapat disusun dari akar akar tersebut adalah....​

Answer 1

Materi : Bentuk dan Persamaan Kuadrat

x¹ = ( 2 + √3 )/2 dan x² = ( 2 - √3 )/2

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( x - x¹ )( x - x² ) = 0

( x - [ 2 + √3 ]/2 )( x - [ 2 - √3 ]/2 ) = 0

( x - 1 - √3/2 )( x - 1 + √3/2 ) = 0

x² - 2x + 1 - 3/4 = 0

x² - 2x + ¼ = 0

4x² - 8x + 1 = 0

Semoga bisa membantu

[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]

Answer 2

Persamaan Kuadrat

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[tex]x {}^{2} + ( \frac{2 + \sqrt{3} }{2} + \frac{2 - \sqrt{3} }{2} ) x+ ( \frac{2 + \sqrt{3} }{2} \times \frac{2 - \sqrt{3} }{2} ) = 0[/tex]

[tex]~~~~~~~~~x {}^{2} + \frac{2 + \sqrt{3} + 2 - \sqrt{3} }{2} x+ \frac{(2 + \sqrt{3} ) \times (2 - \sqrt{3}) }{4} = 0[/tex]

[tex]~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~x {}^{2} + \frac{4}{2}x + \frac{4 - 3}{4} = 0[/tex]

[tex]~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~x {}^{2} + 2x + \frac{1}{4} = 0[/tex]

[tex]~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~4x {}^{2} + 8x + 1 = 0[/tex]

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[tex]\boxed{\colorbox{ccddff}{Answered by Danial Alf'at}}\boxed{\colorbox{ccddff}{15/03/23}}[/tex]