Jawab:
persmaan kuadrat
faktorisasi
akar akar
Penjelasan dengan langkah-langkah:
2/(x) + 1 / ( x+ 3) = 1/(2)
i) KPK penyebut = (x)(x+3)(2)
ii) 2/(x) + 1 / ( x+ 3) = 1/(2) kalikan kedua ruas dengan KPK penyebut
(x)(x+3)(2)[ 2/(x) + 1 / ( x+ 3)] = (x)(x+3)(2)[ 1/2 ]
{ 2 (2)(x + 3) + 1 (x)(2) = 1 (x)(x + 3)
4(x + 3) + 2x = x² + 3x
4x + 12 + 2x = x² + 3x
6x + 12 = x² + 3x
susun baru --> x² + 3x - 6x - 12= 0
x² -3x - 12 =0
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Jawab:
persmaan kuadrat
faktorisasi
akar akar
Penjelasan dengan langkah-langkah:
2/(x) + 1 / ( x+ 3) = 1/(2)
i) KPK penyebut = (x)(x+3)(2)
ii) 2/(x) + 1 / ( x+ 3) = 1/(2) kalikan kedua ruas dengan KPK penyebut
(x)(x+3)(2)[ 2/(x) + 1 / ( x+ 3)] = (x)(x+3)(2)[ 1/2 ]
{ 2 (2)(x + 3) + 1 (x)(2) = 1 (x)(x + 3)
4(x + 3) + 2x = x² + 3x
4x + 12 + 2x = x² + 3x
6x + 12 = x² + 3x
susun baru --> x² + 3x - 6x - 12= 0
x² -3x - 12 =0