jaka liczbe moli stanowi 128g dwutlenku siarki??
a.1 mol
b.1/2 mola
c.2 mole
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jaka liczbe moli stanowi 128g dwutlenku siarki??
a.1 mol
b.1/2 mola
c.2 mole
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M SO2=64g/mol
1mol SO2-----64g
xmoli SO2-----128g
x = 2mole SO2
Prawidłowa odpowiedź c. 2mole