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t= 30 sekon
I=...?
I= Q/t
= 3/30
=1/10 A
=100 mA
jawabannya a
Q= 3 C
t= 30 sekon
ditanyakan :
I=...?
I= Q/t
= 3/30
=1/10 A
=100 mA
jadi kuat arus yang mengalir adalah 100A (a)