Jawab:
Fungsi komposisi dan invers
(fog)⁻¹ (x) = { g⁻¹ o f⁻¹) (x)
(fog)⁻¹ (x) = g⁻¹ { f⁻¹(x)}
Penjelasan dengan langkah-langkah:
f⁻¹ (x) = ( x- 1 ) / 5
g⁻¹ (x) = (3 - x) /2
.
(fog)⁻¹ (6) = g⁻¹ { f⁻¹(6)}
(fog)⁻¹ (6) = g⁻¹ { (6-1)/5)}
(fog)⁻¹ (6) = g⁻¹ { 5/5 }
(fog)⁻¹ (6) = g⁻¹ {1}
(fog)⁻¹ (6) = (3 - 1)/2
(fog)⁻¹ (6) = 2/2
(fog)⁻¹ (6) = 1
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Jawab:
Fungsi komposisi dan invers
(fog)⁻¹ (x) = { g⁻¹ o f⁻¹) (x)
(fog)⁻¹ (x) = g⁻¹ { f⁻¹(x)}
Penjelasan dengan langkah-langkah:
f⁻¹ (x) = ( x- 1 ) / 5
g⁻¹ (x) = (3 - x) /2
.
(fog)⁻¹ (x) = g⁻¹ { f⁻¹(x)}
(fog)⁻¹ (6) = g⁻¹ { f⁻¹(6)}
(fog)⁻¹ (6) = g⁻¹ { (6-1)/5)}
(fog)⁻¹ (6) = g⁻¹ { 5/5 }
(fog)⁻¹ (6) = g⁻¹ {1}
(fog)⁻¹ (6) = (3 - 1)/2
(fog)⁻¹ (6) = 2/2
(fog)⁻¹ (6) = 1