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Verified answer
LogAritMaa'log f(x) = b'log f(x)
f(x) = 1
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²log (x² - 2x - 23) = ³log (x² - 2x - 23)
x² - 2x - 23 = 1
x² - 2x - 24 = 0
(x - 6)(x + 4) = 0
x = 6 atau x = -4
Nilai x yg memenuhi :
x = 6 dan x = -4