Question

2 log 3 =x dan 2log 10 =y . nilai 6log 120 adalah.....

Answer 1

^6log 120
=²log 120 / ²log 6
=(²log 2²×3×10) / (²log 2×3)
=(²log 2² + ²log 3 + ²log 10)/(²log 2 +²log 3)
=(2 ²log 2 +²log 3+²log 10)/(²log 2+²log3)
=(2 + x + y) / (1+ x)