Respuesta:
1.-
[tex]2 \frac{1}{2} = \frac{5}{2} [/tex]
[tex] \frac{5}{2} - \frac{3}{4} = \frac{20 - 6}{8} = \frac{14}{8} [/tex]
RESULTADO: Quedó 14/8 kg.
2.-
[tex] \frac{1}{3} + \frac{1}{4} = \frac{4 + 3}{12 } = \frac{7}{12} + \frac{1}{5} = \frac{35 + 12}{60} = \frac{47}{60} [/tex]
[tex] \frac{1}{1} - \frac{47}{60} = \frac{60 - 47}{60} = \frac{13}{60} [/tex]
RESULTADO: Le falta leer 13/60.
3.-
[tex] \frac{7}{9} + \frac{6}{7} = \frac{49 + 54}{63} = \frac{103}{63} [/tex]
[tex] \frac{2}{1} - \frac{103}{63} = \frac{126 - 103}{63} = \frac{23}{63} [/tex]
RESULTADO:
*Los dos terrenos juntos miden 103/63 ha.
*Para tener 2 hectáreas les falta 23/63.
Espero que te ayude :)
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Verified answer
Respuesta:
1.-
[tex]2 \frac{1}{2} = \frac{5}{2} [/tex]
[tex] \frac{5}{2} - \frac{3}{4} = \frac{20 - 6}{8} = \frac{14}{8} [/tex]
RESULTADO: Quedó 14/8 kg.
2.-
[tex] \frac{1}{3} + \frac{1}{4} = \frac{4 + 3}{12 } = \frac{7}{12} + \frac{1}{5} = \frac{35 + 12}{60} = \frac{47}{60} [/tex]
[tex] \frac{1}{1} - \frac{47}{60} = \frac{60 - 47}{60} = \frac{13}{60} [/tex]
RESULTADO: Le falta leer 13/60.
3.-
[tex] \frac{7}{9} + \frac{6}{7} = \frac{49 + 54}{63} = \frac{103}{63} [/tex]
[tex] \frac{2}{1} - \frac{103}{63} = \frac{126 - 103}{63} = \frac{23}{63} [/tex]
RESULTADO:
*Los dos terrenos juntos miden 103/63 ha.
*Para tener 2 hectáreas les falta 23/63.
Espero que te ayude :)