Diketahui deret geometri 6 + 3 + 1 1/2 + ... jumlah deret tersebut sampai suku tak terhingga adalah .... Question from @Marlin8

February 2019 2 30 Report

Diketahui deret geometri 6 + 3 + 1 1/2 + ... jumlah deret tersebut sampai suku tak terhingga adalah ...

kikiksubekti $S_{~}= \frac{a}{1-r} = \frac{6}{1-1/2} = \frac{6}{1/2} =12$

Untk mencari ratio(r)= u2:u1=3:6=1:2

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agusadi4 A=6,r=3/6=1/2
s°°=a/(1-r)=6/(1-0,5)=6/0,5=12
maaf kalo salah

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