[ {(5^(1/2) + 2 )^6} - {(5^(1/2) -2 )^6} ] / 80^(1/2) = ... help me again please? thankyou very much.... Question from @gwenlauren36

October 2018 1 19 Report

[ {(5^(1/2) + 2 )^6} - {(5^(1/2) -2 )^6} ] / 80^(1/2) = ... help me again please? thankyou very much god will always bless ya. ^^

Kilos $Dengan\ menggunakan\ segitiga\ pascal\\\\ maka\ kita\ bisa\ mendapatkan : \\\\ (a + b)^{2} = a^{2} + b^{2} + 2ab \\\\ (a + b)^{3} = a^{3} + 3a^{2}b + 3ab^{2} + b^{3} \\\\ (a + b)^{4} = a^{4} + 4a^{3}b + 6a^{2}b^{2} + 4ab^{3} + b^{4} \\\\ .... \\\\ (a + b)^{6} = a^{6} + 6a^{5}b + 15a^{4}b^{2} + 20a^{3}b^{3} + 15a^{2}b^{4} + 6ab^{5} + b^{6} \\\\ dan \\\\ (a - b)^{6} = a^{6} - 6a^{5}b + 15a^{4}b^{2} - 20a^{3}b^{3} + 15a^{2}b^{4} - 6ab^{5} + b^{6}$

$misal : \\\\ \boxed { \sqrt{5} = a\ dan\ 2 = b } \\\\ (a + b)^{6} - (a - b)^{6} \\\\ = (a^{6} + 6a^{5}b + 15a^{4}b^{2} + 20a^{3}b^{3} + 15a^{2}b^{4} + 6ab^{5} + b^{6}) \\\\ dikurangi \\\\ (a^{6} - 6a^{5}b + 15a^{4}b^{2} - 20a^{3}b^{3} + 15a^{2}b^{4} - 6ab^{5} + b^{6}) \\\\ = 12a^{5}b + 40a^{3}b^{3} + 12ab^{5}$

$sehingga : \\\\ \frac{(\sqrt{5} + 2)^{6} - (\sqrt{5} - 2)^{6}}{\sqrt{80}} \\\\ menjadi : \\\\ \frac{12a^{5}b + 40a^{3}b^{3} + 12ab^{5}}{\sqrt{80}} \\\\ = \frac{12.(\sqrt{5})^{5}.2 + 40.(\sqrt{5})^{3}.2^{3} + 12.(\sqrt{5}).2^{5}}{4\sqrt{5}} \\\\ = \frac{12.(\sqrt{5})^{4}.2 + 40.(\sqrt{5})^{2}.2^{3} + 12.2^{5}}{4} \\\\ = (3.(\sqrt{5})^{4}.2) + (10.(\sqrt{5})^{2}.8) + (3.32) \\\\ = (3.25.2) + (10.5.8) + 96 \\\\ = 150 + 400 + 96 \\\\ \boxed { \boxed { \bold { = 646} } }$

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[ {(5^(1/2) + 2 )^6} - {(5^(1/2) -2 )^6} ] / 8.(5^(1/2)) = ... help me again please? thankyou very much god will always bless ya. ^^ * yg hari itu salah soal

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gwenlauren36 October 2018 | 0 Replies

Bantuin yg nomor 18 dong, beneran gak ngertii, makasii x gbu❤

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gwenlauren36 October 2018 | 0 Replies

[{ 7^x + 2.(7^x) + 3.(7^x) + 4.(7^x) + ... + 49.(7^x) } / 25 ] = 343 nilai x yang memenuhi persamaan adalah ... help please, thnks x

Answer

gwenlauren36 October 2018 | 0 Replies

Bantuin yg nomor 11 dan 12 dongg pleasee makasi banyakk

No.1 : (9^x + 9^-x) = 98, maka nilai (3^x + 3^-x) = ... no.2 : x+y=1 dan x^3 + y^3 = 49, maka x^2 + y^2 = ... makasii

[{(0,09^(3/2)).(x-3)} / (0,3^(4x+1))] = 1 nilai x yg memenuhi persamaan adalah ... (no.2)

[ {(5^(1/2) + 2 )^6} - {(5^(1/2) -2 )^6} ] / 8.(5^(1/2)) = ... help me again please? thankyou very much god will always bless ya. ^^ * yg hari itu salah soal

Bantuin yg nomor 18 dong, beneran gak ngertii, makasii x gbu❤

[{ 7^x + 2.(7^x) + 3.(7^x) + 4.(7^x) + ... + 49.(7^x) } / 25 ] = 343 nilai x yang memenuhi persamaan adalah ... help please, thnks x

Cara cepat mengerjakan : (48 . 27 . 35 . 175 . 245) ^(1/2) adalah .. thankyouu

Jika a^(3/2) = b^(-3/2) . c^(3/4), maka c dinyatakan dalam a dan b adalah... help please? :) thanks

Jika diketahui x + y = 3, maka nilai dari [{9^(x-2y)} . {2^(2x-y+2)}] / [{3^(x-5y)} . {2^(x-2y+1)}]

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