Question

Sin (1/2X-π) cos (1/2-π)dx ?

Answer 1

Verified answer

• sin (1/2 x - π)

dsin (1/2 x - π) /dx = (1/2) cos (1/2 x - π)
cos (1/2 x - π) dx = (1/2)dsin (1/2 x - π)

∫sin (1/2 x - π) (cos (1/2 x - π) dx)
= ∫ sin (1/2 x - π) . (1/2)dsin (1/2 x - π)
= (1/2)(1/(1+1)(sin (1/2 x - π))^(1+1) + C
= (1/2)(1/2)(sin (1/2 x - π))^2 + C
= (1/4)sin² (1/2 x - π) + C