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AC = C - A = (2,0,5) - (2,-1,4) = (0,1,1)
= √5
AC = √{0² + 1² + 1²}
= √2
BC = √{2² + 1² + 2²}
= √5
BC² = AB² + AC² - 2.AB.AC cos α
5 = 5 + 2 - 2.√5 . √2 cos α
5 = 7 - 2.√10 cos α
2√10 cos α = 7 - 5
2√10 cos α = 2
cos α = 2/(2√10)
cos α = (1/10)√10