2. Diketahui segitiga ABC siku-siku di A dengan panjang BC = 40 cm dan AC = 24 cm. Titik D terletak pada sisi AB sedemikian sehingga panjang CD = 25 cm. Berapakah panjang BD?
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Jawab:
Penjelasan dengan langkah-langkah:
AC = 24
BC = 40
CD = 25
AB² = BC² - AC²
AB² = 40² - 24²
AB² = 1600 - 576
AB² = 1024
AB = √1024
AB = 32
AD² = CD² - AC²
AD² = 25² - 24²
AD² = 625 - 576
AD² = 49
AD = √49
AD = 7
AB = AD + BD
32 = 7 + BD
BD = 32 - 7
BD = 25 cm