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A-5=(B+5).........2(A-5)=B+5......2A-10=B+5......2A-B=5+10.....2A-B=15
2
sustituimos A=B+6,en la segunda ecuacion
2A-B=15
2(B+6)-B=15
2B+12-B=15
2B-B=15-12
B=3
si B=3........A=B+6......A=3+6......A=9
A=9 B=3
inicialmente habia 9 niños en el salon "A"
A = 6 + B
restandole los 5 q se pasaron quedaria
A = 1 + B
por lo tanto
(B + 1) . 2 = B + 5
2B + 2 = B + 5
B =3
A = 9