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x-3y=1
5/2=2,5
x= 2,dan y=1
2/1+1/2=2,5 atau 5/2
x-3y=1
2-3*1=-1
(3y+1)/y + y/(3y+1)=5/2
[(3y+1)(3y+1)+y^2]/y(3y+1)=5/2
[9y^2+6y+1+y^2]=5/2(3y^2+y)
2[10y^2+6y+1]=5(3y^2+y)
20y^2 + 12y + 2 = 15y^2 + 5y
5y^2 +7y +2 = 0
(5y + 2)(y + 1)=0
y = -2/5 atau y = -1
x = 3(-2/5)+1 atau x=3(-1)+1
x = -6/5 + 1 atau x = -3 + 1
x = -1/5 atau x = -2