Jawab:
a. y-0= (x-0)
2y=3x → 2y-3x = 0
b. y-(-10)= (x-0)
2y+20=3x
3x-2y-20=0
c. y-(-3)= (x-5)
2y+6=3(x-5)
2y+6=3x-15
3x-2y-9=0
Penjelasan dengan langkah-langkah:
pers. garis lurus y-y₁=m(x-x₁)
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Jawab:
a. y-0= (x-0)
2y=3x → 2y-3x = 0
b. y-(-10)= (x-0)
2y+20=3x
3x-2y-20=0
c. y-(-3)= (x-5)
2y+6=3(x-5)
2y+6=3x-15
3x-2y-9=0
Penjelasan dengan langkah-langkah:
pers. garis lurus y-y₁=m(x-x₁)