Question

Integral x^-sinx dx batas bawah 1/2π dan batas atas π berapa hasilnya?

Answer 1

Verified answer

Jawab

(1/2 π...π) ∫ (x² - sin x) dx
= [ 1/3 x³ + cos x ] (π....1/2 π)

= 1/3 (π³ - (1/2 π)³) + { cos π - cos (1/2 π)}
= 1/3 (π³ - 1/8 π³) + {-1 - 0}
= 1/3 (7/8 π³) + (-1)
= 7/24 π³  -  1