X/3+x/5+1= 3x/4-1/2 ayuda con proceso
michel2004
3x-1 = 5x+2/x-2> Realizado operaciones y simplificando:(3x-1)(x-2) = 5x+23x²-7x+2 = 5x+23x²-7x-5x+2-2 = 03x²-12x = 0 > Aplicando la fórmula:x = [-(-12)± (-12)]/2(3)x = [12±(-12)]/6–>x₁ = [12+(-12)]/6 = [12-12]/6 = 0/6 = 0x₂ = [12-(-12)]/6 = [12+12]/6 = 24/6 = 4
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