Question

Persamaan garis yang melalui titik (-2,1) dan bergradien 3/2 adalah

Answer 1

Y - y1 = m (x-x1)
y- 1 =  ( x + 2)
2 (y-1) = 3 (x+2)
2y - 2 = 3x + 6
2y - 3x = 6 + 2
2y - 3x -8 = 0

Answer 2

M=3/2 (-2,1)
y-y1 = m (x-x1)
y-1 = 3/2 (x-(-2))
y-1 = 3/2 2x
                     diklikan 1
2(y-1) = 3(x+2)
2y-2 = 3x+6
-3x+2y-6-2=0
-3x+2y-12=0