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log[a.(√b/a )]
log a +log (Vb/a)= log a + 1/2( log b-log a)=
sustituimos
4+1/2( 3-4)= 7/2
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2.- log √(b/2) a
log V(b/2)+log a= 1/2( logb-log2) +log a=
sustituimos valores
1/2 ( 3-log2)+4= 3/2-log2+4= 11/2+log2=11/4+0.3=12,2/4