Question

13. Perhatikan gambar berikut. 10 cm 14 cm Luas permukaan bangun pada gamabr di atas adalah.... (π = 2/2)​

Answer 1

Verified answer

Penyelesaian:

d = 14 cm

r = 7 cm

t selimut tabung = 10 cm

t kerucut = 34 - 10 = 24 cm

Panjang garis pelukis kerucut:

• s = [tex] \sqrt{r² + t \:kerucut²}[/tex]
• s = [tex] \sqrt{7² + 24²}[/tex]
• s = [tex] \sqrt{49 + 576}[/tex]
• s = [tex] \sqrt{625}[/tex]
• s = 25 cm

Luas selimut tabung:

• Ls = 2πrt
• Ls = 2 × 22/7 × 7 × 10
• Ls = 44 × 10
• Ls = 440 cm²

Luas permukaan kerucut:

• Lp = πr(r + s)
• Lp = 22/7 × 7 (7 + 25)
• Lp = 22 (32)
• Lp = 704

Luas permukaan bangun tsb:

• Lp = Ls tabung + Lp kerucut
• Lp = 440 + 704
• Lp = 1.144 cm²

Jawaban: 1.144 cm²