Question

2. 3log6 -1/2. 3log16+3log18-3log2

Answer 1

Verified answer

Kelas 10 Matematika
Bab Logaritma

^ = pangkat

2 . ^3log 6 - (1/2) . ^3log 16 + ^3log 18 - ^3log 2
= ^3log 6² - ^3log 16^(1/2) + ^3log (18/2)
= ^3log 36 - ^3log 4 + ^3log 9
= ^3log (36/4) + ^3log 3²
= ^3log 9 + 2 . ^3log 3
= ^3log 3² + 2
= 2 . 1 + 2
= 4