Jawab:
Penjelasan dengan langkah-langkah:
vektor
sudut dua vektor
a.b = |a|.|b|. cos (<a,b)
__
soal
A= (2, - 3, 3 )
B =(3, -2, -4)
a. b = 2(3) - 3(-2) + 3(-4)
a. b = 6 + 6 - 12
a. b= 0
cos <(a,b) = (a.b ) / |a| |b|
cos <(a,b) = 0 / |a| |b|
cos <(a,b) = 0 = cos (90)
<(a,b) = 90°
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Jawab:
Penjelasan dengan langkah-langkah:
vektor
sudut dua vektor
a.b = |a|.|b|. cos (<a,b)
__
soal
A= (2, - 3, 3 )
B =(3, -2, -4)
a. b = 2(3) - 3(-2) + 3(-4)
a. b = 6 + 6 - 12
a. b= 0
cos <(a,b) = (a.b ) / |a| |b|
cos <(a,b) = 0 / |a| |b|
cos <(a,b) = 0 = cos (90)
<(a,b) = 90°