Ayuda es para hoy examen final para terminar el año (-3a3 + 4b2 – 6) + (a3 - 5b2 + 10) =
(1/5 x^3-8y^2-6)-(y^2-5x^3+10)=
(12 a3b2) . (2a3b – 4ab2 + 5) =
(7/12 x^5-4).(2/3 x^3-1/4 x^6 )=
(-3/2 a^6 b^5-3/4 a^8 b^3 )÷ (-1/3 a^6 b^2 )=
(-2/7 x^3 y^2+3/4 x^4 y)÷(-28xy)=
5/8⋅6/5-1/2=
-7/5+3/4.2/5÷3/2=
2,75 – 5,21 . 0,4 =
– 8,25 + 5,45 ÷ 0,5 . 3,8 =
(1/5 x^3-8y^2-6)-(y^2-5x^3+10)=
(12 a3b2) . (2a3b – 4ab2 + 5) =
(7/12 x^5-4).(2/3 x^3-1/4 x^6 )=
(-3/2 a^6 b^5-3/4 a^8 b^3 )÷ (-1/3 a^6 b^2 )=
(-2/7 x^3 y^2+3/4 x^4 y)÷(-28xy)=
5/8⋅6/5-1/2=
-7/5+3/4.2/5÷3/2=
2,75 – 5,21 . 0,4 =
– 8,25 + 5,45 ÷ 0,5 . 3,8 =
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