[tex]\dfrac{1}{4}+\dfrac{2}{3}-\dfrac{116}{100}+\dfrac{5}{2}+\dfrac{26}{10}-\dfrac{125}{100}+2\\\\\\\dfrac{25-116+250+260-125+200}{100}+\dfrac{2}{3}\\\\\\\dfrac{494}{100}+\dfrac{2}{3}=\dfrac{1482+200}{300}=\dfrac{1682}{300}=5,60\overline{6}[/tex]
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[tex]\dfrac{1}{4}+\dfrac{2}{3}-\dfrac{116}{100}+\dfrac{5}{2}+\dfrac{26}{10}-\dfrac{125}{100}+2\\\\\\\dfrac{25-116+250+260-125+200}{100}+\dfrac{2}{3}\\\\\\\dfrac{494}{100}+\dfrac{2}{3}=\dfrac{1482+200}{300}=\dfrac{1682}{300}=5,60\overline{6}[/tex]