1)mNaCl=58,5umNa=23u58,5g NaCl ------- 23g Naxg NaCl -----------11,5g NaClx = 29,25g NaClx = 29,25u2)a) mNaH2PO4=120u%P = (31/120)*100% = 25,83%b) mNa2HPO4=142u%P = (31/142)*100% = 21,83%c) mNa3PO4=164u%P = (31/164)*100% = 18,9%Najwięcej fosforu zawiera związek a)
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1)
mNaCl=58,5u
mNa=23u
58,5g NaCl ------- 23g Na
xg NaCl -----------11,5g NaCl
x = 29,25g NaCl
x = 29,25u
2)
a) mNaH2PO4=120u
%P = (31/120)*100% = 25,83%
b) mNa2HPO4=142u
%P = (31/142)*100% = 21,83%
c) mNa3PO4=164u
%P = (31/164)*100% = 18,9%
Najwięcej fosforu zawiera związek a)