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2.oblicz zawartość % w kwasie chlorowodorowym
80 g+ 20 g = 100 g.
w 100 g roztworu - 20 g kwasu.
Cp = 20 %
mHCl = 1 + 35= 36
mH = 1/36 * 100% = 2,8%
mCl = 100 % - 2,8 % = 97,2 %