Question

1.tentukan sudut terkecil dari jarum jam berikut!(berikan caranya)
o>05.20
o>10.40
o>12.35

Answer 1

1. 05.20
=(5 × 30° + 20/60 × 30°) - 4 × 30°
=(150° + 10°) - 120°
=160° - 120°
=40°

2. 10.40
=(10 × 30° + 40/60 × 30°) - 8 × 30°
=(300° + 20°) - 240°
=320° - 240°
=80°

3. 12.35
=(12 × 30° + 35/60 × 30°) - 7 × 30°
=(360° + 17,5°) - 210 °
=377,5° - 210°
=167,5 °