Question

1.tentukan persamaan garis yg melalui titik (3,6) dg gradien 3
2.tentukan persamaan garis yg melalui titik (12,8) dan (4,5)

mohon bantuannya kawan:)

Answer 1

1. y-y=m(x-x)
y-6 = 3(x-3)
y-6 = 3x-9
y=3x-9+6
y=3x-3

2. y-y1 x-x1
____ = ____
y2-y1 x2-x1

y-8 x-12
____ = _____
5-8 4-12

y-8 x-12
___ = _____
-3 -8

-3(x-12) = -8(y-8)
-3x+36 = -8y+64
8y-3x+36-64 =0
8y-3x-28=0

Answer 2

Y - y1=m(x-x1)
y-6=3(x-3)

y-6=3x-9+6
y=3x-3