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1][gradien dr garis yg melalui (4,3) dan (-2,-5) :
m = (3 - (-5))/(4 - (-2))
m = 8/6
m = 4/3
sejajar : gradien sama
pers garis dg gradien m = 4/3 dan melalui (x1,y1) = (-2,1) :
y - y1 = m(x - x1)
y - 1 = 4/3 (x + 2)
3y - 3 = 4x + 8
4x - 3y + 11 = 0
2][
m yg mlalui (3,-4) dan (-1,2)
m1 = (-4 - 2)/(3 - (-1))
m1 = -3/2
tegaklurus : m2 = -1/m1 = 2/3
pers garis dg m = 2/3 dan melalui (-4,-3) :
y - (-3) = 2/3 (x - (-4))
3y + 9 = -2x - 8
2x + 3y + 17 = 0