Question

1.tentukan penjabaran perpangkaan bentuk aljabar berikut

a. (2x + 3y)^3=
b. (5a - 3b)²=
c. (-2p - 3q)^4=

Answer 1

A. (2x + 3y)^3
= (2x + 3y) (2x + 3y) (2x + 3y)
= 8x^3 + 6xy + 6xy + 6xy + 6xy + 27y^3
= 8x^3 + 24xy + 27y^3

b. (5a - 3b)^2
= (5a - 3b) (5a - 3b)
= 25a^2 - 15ab - 15ab + 9b^2
= 25a^2 - 30ab + 9b^2

c. (-2p - 3q)^4
= (-2p - 3q) (-2p - 3q) (-2p - 3q) (-2p - 3q)
= (4p^2 + 12pq + 9q^2) (4p^2 + 12pq + 9q^2)
= 16p^4 + 96p^3q + 216p^2q^2 + 216pq^3 + 81q^4

Answer 2

A. (2x + 3y)^3 = 8x³ + 36x²y + 54xy² + 27y³
b. (5a - 3b )^2 = 25a² - 30ab + 9b²
c. (-2p - 3q)^4 = 16p⁴ + 48p³q + 108p²q² + 108pq³ + 81q⁴ 


Hafalan diluar kepala
( a + b )² = (a² + 2ab  + b²)                          =       1 + 2 + 1
( a + b )³ = (a³ + 3a² b + a 3b² + b³ )               =    1 + 3 + 3 + 1
( a + b )⁴ = (a⁴ + 4a³ b + 6a² 6b² + a 4b³ + b⁴ )    = 1 + 4 + 6 + 4 + 1
....
dst