Question

1.persamaan sumbu simetri dari fungsi kuadrat y = 2x² -4x +2021 adalah...
2.kurva f(x) = -x² +bx - 21 mempunyai sumbu simetri x = 5 nilai b =
pakai cara​

Answer 1

1.

xsim = -b/a = -(-4)/2 = 2

2.

xsim = 4

-b/a = 4

-b/-1 = 4

b = 4.