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f(1)=0
f(0)=-2
f(1)=0
jb:
f(x)=ax+b
f(1)=a.1+b=0
f(1)=a+b=0....(1)
f(0)=-2
jb:
f(x)=ax+b
f(0)=a.0+b=-2
f(0)=b=-2....(2)
maka b=2
a?
a?= a+b=0....(Dari yang 1 diatas)
a?= a+(-2)=0
a?= a= 0+2
a?= a= 2
hasil
a=2
b=-2
rumus fungsi
f(x)=ax+b
f(x)=2x-2