Zad.1.mH₂CO₃=2u+12u+48u=62u%H = (2/62)*100% = 3,2%%C = (12/62)*100% = 19,4%%O = (48/62)*100% = %= 77,4%
Zad.2.mN₂O₅=108um2HNO₃=63uN₂O₅ + H₂O ---> 2HNO₃108g N₂O₅ ------ 126g HNO₃xg N₂O₅ --------- 12,6g HNO₃x = 10,8g N₂O₅
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Zad.1.
mH₂CO₃=2u+12u+48u=62u
%H = (2/62)*100% = 3,2%
%C = (12/62)*100% = 19,4%
%O = (48/62)*100% = %= 77,4%
Zad.2.
mN₂O₅=108u
m2HNO₃=63u
N₂O₅ + H₂O ---> 2HNO₃
108g N₂O₅ ------ 126g HNO₃
xg N₂O₅ --------- 12,6g HNO₃
x = 10,8g N₂O₅