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mCH3COOH=24u+4u+32u=60u
%C = (24/60)*100% = 40%
Zad. 2
a) HCOOH --H₂O--> H⁺ + HCOO⁻
b) C₂H₅COOH --H₂O--> H⁺ + C₂H₅COO⁻
c) (CH₃COO)₂Ca --H₂O--> Ca²⁺ + 2CH₃COO⁻
d) HCOONa --H₂O--> Na⁺ + HCOO ⁻
Zad. 3
a)
2Na + 2C₂H₅COOH ---> 2C₂H₅COONa + H₂
Na₂O + 2C₂H₅COOH ---> 2C₂H₅COONa + H₂O
NaOH + C₂H₅COOH ---> C₂H₅COONa + H₂O
b)
Ca + 2HCOOH ---> (HCOO)₂Ca + H₂
CaO + 2HCOOH ---> (HCOO)₂Ca + H₂O
Ca(OH)₂ + 2HCOOH ---> (HCOO)₂Ca + 2H₂O