Zad.1Z def. stęż. procent.0,16g Ca(OH)2------100,16g roztworu(0,16 Ca(OH)2 + 100g wody)xg Ca(OH)2----------100g roztworux ≈ 0,16g Ca(OH)2x ≈ 0,16% Zad.2mCa : mO : mH = 40 : 32 : 2mCa : mO : mH = 20 : 16 : 1
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Zad.1
Z def. stęż. procent.
0,16g Ca(OH)2------100,16g roztworu(0,16 Ca(OH)2 + 100g wody)
xg Ca(OH)2----------100g roztworu
x ≈ 0,16g Ca(OH)2
x ≈ 0,16%
Zad.2
mCa : mO : mH = 40 : 32 : 2
mCa : mO : mH = 20 : 16 : 1