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2. Etan- C2H6
Stosunek masowy: C:H
mC2H6=2*12u+6*1u
C:H=24:6=4:1
3. Chyba chodziło o butan
Butan- C4H10=4*12u+10*1u=58u
48u-x%
58u-100%
x=82,76%C