1. a) mMgCl2=24u+2*35,5u=95u b)mCa(NO3)2=40u+2*14u+6*16u=164u c) mFe2(SO4)3=2*56u+3*32u+12*16u=400u
2. a)mCu(NO3)2=64u+2*14u+6*16u=188u % Cu = (64/188)*100% = 34% b) mAlCl3=27u+3*35,5u=133,5u
% Al = (27/133,5)*100% = 20,2%
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1.
a) mMgCl2=24u+2*35,5u=95u
b)mCa(NO3)2=40u+2*14u+6*16u=164u
c) mFe2(SO4)3=2*56u+3*32u+12*16u=400u
2.
a)mCu(NO3)2=64u+2*14u+6*16u=188u
% Cu = (64/188)*100% = 34%
b) mAlCl3=27u+3*35,5u=133,5u
% Al = (27/133,5)*100% = 20,2%