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a) (NH₄)₂SO₃ ---> 2 NH₄⁺ + SO₃²⁻
b) Fe(NO₃)₃ ---> Fe³⁺ + 3 NO₃⁻
c) BaS ---> Ba²⁺ + S²⁻
d) Al₂(SO₄)₃ ----> 2 Al³⁺ + 3 SO₄²⁻
2.
masa NH₄NO₂ = 14g + 4 * 1g + 14g + 2 * 16g = 64g
azot, masa = 2 * 14g = 28g
64g --- 100%
28g ---- x %
x = (28g * 100%) : 64g = 43,75%
wodór, masa = 4 * 1g = 4g
64g --- 100%
4g ---- x %
x = (4g * 100) : 64g = 6,25%
tlen, masa = 2 * 16g = 32g
64g --- 100%
32g ---- x %
x = 50%
3.
a) MgOHCl
b) Ca(H₂PO₄)₂
c) FeSO₄