Question

1)napisz reakcje spalania całkowitego:metan,

etan,

propan,

butan

2)

napisz reakcje spalania niecałkowitego:

metan

etan

propan

butan

Answer 1

ETAN:C₂H₆+⁷/₂O₂---> 2 CO₂ + 3 H₂O /×2 2 C₂H₆+7 O₂ ---> 4CO₂ + 6 H₂O BUTAN: C₄H₁₀ +¹³/₂O₂--->4CO₂+ 5H₂O /×2          2 C₄H₁₀ + 13O₂ ---> 8CO₂+ 10H₂O Propan C3H8+5O2->3CO2+4H2O , 2C3H8+7O2->6CO+8H2O

Answer 2

1.Etan- C2H6

C2H6+3,5O2--->2CO2+3H2O/*2

2C2H6+7O2--->4CO2+6H2O

Propan-C3H8

C3H8+5O2--->3CO2+4H2O

Butan-C4H10

C4H10+6,5O2--->4CO2+5H2O/*2

2C4H10+13O2--->8CO2+10H2O

2.Metan-CH4

CH4+O2--->C+2H2O- sp.niecałkowite

CH4+1,5O2--->CO+2H2O/*2

2CH4+3O2--->2CO+4H2O- półspalanie(zalicza się do spalania niecałkowitego)

Etan-C2H6

C2H6+1,5O2--->2C+3H2O/*2

2C2H6+3O2--->4C+6H2O

C2H6+2,5O2--->2CO+3H2O/*2

2C2H6+5O2--->4CO+6H2O

Propan-C3H8

C3H8+2O2--->3C+4H2O

C3H8+3,5O2--->3CO+4H2O/*2

2C3H8+7O2--->6CO+8H2O

Butan-C4H10

C4H10+2,5O2--->4C+5H2O/*2

2C4H10+5O2--->8C+10H2O

C4H10+4,5O2--->4CO+5H2O/*2

2C4H10+9O2--->8CO+10H2O

 

Na pewno jest dobrze. Myślę, że pomogłam. Proszę o naj:)