1.Ile tlenu zuzyto do spalenia 12 kg etenu?
Thx 4 answers ;)
CH2=CH2 + 3 O2 ---> 2 CO2 + 2 H2O
n C2h4= 12000/ 28= 428,57 moli
n H2O = 3* 428,57 = 1285,71 moli
1285,71 * 32 = 41142,86 g = 41,14286 kg
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CH2=CH2 + 3 O2 ---> 2 CO2 + 2 H2O
n C2h4= 12000/ 28= 428,57 moli
n H2O = 3* 428,57 = 1285,71 moli
1285,71 * 32 = 41142,86 g = 41,14286 kg