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f(1) = (-2 × 1) + 3
= -2 + 3
= 1
b. f(x) = 1
= -2x + 3 ⇒ 1 = -2x + 3
1 - 3 = -2x
-2 = -2x
1 = x ⇒ x = 1
2. f(x) = 2x + m
f(3) = 4
= (2 × 3) + m
= 6 + m ⇒ 4 = 6 + m
4 - 6 = m
-2 = m ⇒ m = -2
Fungsi f dapat didefinisikan sebagai f(x) = 2x + (-2)
= 2x - 2