Question

Turunan dari y: [sinx/1+cosx]^2

Answer 1

Y=(sin x/(1+cos x))^2
y=sin^2 (x)/(1+cos (x))^2

y'=(2 sin x cos x (1+cos (x)) - (sin^2 (x) (-sin (x)))/(1+cos (x))^4
  =( sin (2x) (1+cos (x) + sin^3 (x))/(1+ cos (x))^4