Question

1.Bentuk sederhana dari
A.5X-2(X-4)
B.7(y+3)-4(3y+6)
2.Nilai 3+2b pangkat 2 jika b=-3
3. Nilai p jika 9p+7=-4

Answer 1

A) 5x-2(x-4) = 5x-2x+8 = 3x+8 B)7(y+3)-4(3y+6) = 7y+21-12y-24 = 7y-12y+21-24= - 5y-3

Answer 2

1.a.5x-2(x-4)=5x-2x+8=3x+8
1.b.7(y+3)-4(3y+6)=7y+21-12y-24=-5y-3
2.3+2b²=3+2(-3)²=3+2×9=21
3.9p+7=-4⇒9p=-11⇒p=-11/9