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3² . 3²^-x - 36. 3^-x + 27 > 0
misal 3^-x = a
9 a² - 36a + 27 > 0
a² - 4a + 3 > 0
(a - 3) (a - 1) > 0
a < 1 atau a > 3
3^-x < 1 atau 3^-x >3
3^-x < 3^0 atau 3^-x > 3^1
-x < 0 -x > 1
x > 0 x <-1
Jawaban B
3^2-2x - 4 • 3^2-x + 27 > 0
3^2 • 3^-2x - 4 • 3^2 • 3^-x + 27 > 0
9p^2 - 36p + 27 > 0
p^2 - 4p + 3 > 0
(p - 1)(p - 3)
p = 1 atau p = 3
3^-x = 3^0 v 3^-x = 3^1
x = 0 atau x = -1
bila x = 1, maka
3^0 - 4 • 3^1 + 27 > 0
1 - 12 + 27 > 0
38 > 0 (Benar)
bila x = -2, maka
3^2 • 3^4 - 4 • 3^4 + 27 > 0
5 • 81 + 27 > 0 (Benar)
jadi jawabannya x < -1 atau x > 0 (B)