Odparowano 100 g wody z 300 g 10 - procentowego roztworu. Oblicz stężenie procentowe otrzymanego roztworu.
1 kl gimnazjum CHEMIA NOWEJ ERY zad 3, 4, 5 / 170 (WZÓR : Cp = ms * 100%) _____________ mr
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mr₁=300g
Cp₁=10%
ms₁=?
Cp₂=?
Cp=ms/mr * 100% /*mr
Cp*mr=ms*100% /:100%
ms=Cp*mr/100%
ms₁=10%*300g/100%
ms₁=30g
ms₂=ms₁=30g
mr₂=mr₁-100g=200g
Cp₂=?
Cp=ms/mr * 100%
Cp₂=30g/200g * 100%
Cp₂=15%