Penjelasan dengan langkah-langkah:
Sederhanakan=> [tex]\sf 16p - 12 + 13p^2 = \boxed {\bf 13p^2 + 16p - 12 = 0}[/tex]
Gunakan rumus a, b, c. Dengan a = 13; b = 16; c = -12, maka:=> [tex]\large {\boxed {\sf \bf x = \frac{-b _{-}^{+} \sqrt{b^2 - 4ac} }{2a} }}\\\sf \bf x = \frac{-(16) _{-}^{+} \sqrt{(16)^2 - 4(13)(-12)} }{2(13)}\\\sf \bf x = \frac{-16 _{-}^{+} \sqrt{256 + 624} }{26}\\\sf \bf x = \frac{-16 _{-}^{+} \sqrt{880} }{26}\\\sf \bf x = \frac{-16 _{-}^{+} 4\sqrt{55} }{26}\\\\\sf \bf x_1 = \frac{-16 + 4\sqrt{55} }{26} = \boxed {\sf \bf \frac{-8 + 2 \sqrt{55} }{13}} \\\sf \bf x_2 = \frac{-16 - 4\sqrt{55} }{26} = \boxed {\sf \bf \frac{-8 - 2 \sqrt{55} }{13}}[/tex]
[tex] \large {\boxed {\blue {\star \:Answered \: By: \: \bold {sulkifli2018} \star} } } [/tex]
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Penjelasan dengan langkah-langkah:
Sederhanakan
=> [tex]\sf 16p - 12 + 13p^2 = \boxed {\bf 13p^2 + 16p - 12 = 0}[/tex]
Gunakan rumus a, b, c. Dengan a = 13; b = 16; c = -12, maka:
=> [tex]\large {\boxed {\sf \bf x = \frac{-b _{-}^{+} \sqrt{b^2 - 4ac} }{2a} }}\\\sf \bf x = \frac{-(16) _{-}^{+} \sqrt{(16)^2 - 4(13)(-12)} }{2(13)}\\\sf \bf x = \frac{-16 _{-}^{+} \sqrt{256 + 624} }{26}\\\sf \bf x = \frac{-16 _{-}^{+} \sqrt{880} }{26}\\\sf \bf x = \frac{-16 _{-}^{+} 4\sqrt{55} }{26}\\\\\sf \bf x_1 = \frac{-16 + 4\sqrt{55} }{26} = \boxed {\sf \bf \frac{-8 + 2 \sqrt{55} }{13}} \\\sf \bf x_2 = \frac{-16 - 4\sqrt{55} }{26} = \boxed {\sf \bf \frac{-8 - 2 \sqrt{55} }{13}}[/tex]
[tex] \large {\boxed {\blue {\star \:Answered \: By: \: \bold {sulkifli2018} \star} } } [/tex]