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Mg + 2 HNO₃ → Mg(NO₃)₂ + H₂
m Mg = 24g
m Mg(NO₃)₂ = 144g
Proporcja
24g Mg- 144g soli
2,4g Mg- x
x=14,4g azotanu magnezu co jest równe ilości azotanu sodu
2 HNO₃ + 2 Na→ 2 NaNO₃ + H₂
m 2 HNO₃ = 2 × 1g + 2 × 14g + 6 × 16g = 2g + 28g + 96g = 126g
m 2 NaNO₃ = 2 × 23g + 2 × 14g + 6 × 16g = 46g + 28g + 96g = 170g
126 g HNO3- 170g soli
x g HNO3 - 14,4g
x=10,7 g HNO3