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|.....↓.................↓
|(160 - x)⇒ 2(160 - x)
|
| C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O
|....↓.................↓
| x ⇒⇒⇒⇒ 5x
...................-------- +
...................500 ml
2(160 - x) + 5x = 500
320 - 2x + 5x = 500
3x = 180
diperoleh volum propana C₃H₈, x = 60 ml
sehingga persentase gas propana dalam campuran adalah,
(60/160) x 100% = 37,5%
____selesai____
mohon ditandai sebagai jawaban terbaik ya, agar dapat menambah semangat...semoga membantu :-)